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I don't know how much savings it will be, but I would just get stainless if I were you. It also may depend on what brand for how much less it will weigh.

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I ride my bike on the track and I the only performance modification I have would have to be my racing tires. Otherwise my bike is pretty much stock, minus the lights, passenger pegs, and mirrors. Now I DO notice the difference but that is only because I'm pushing my bike hard on the track. If you're pushing your bike on the street to the point in which you can actually tell the difference with any weight savings...your endangering yourself and others.

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thanks. thats what i figured.. i wasnt sure.Everything else equal you can get a better performance gain (weight loss) by taking a dump before you ride.

It's a noticable difference in your hand when you hold one vs. the other, but not terribly noticable (if at all) on the bike.

R

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Ti-is lighter

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Well let's transform that 5 or 10 pounds quoted earlier into a relative quantity called percentage (so fun!) Because the snow is melting here I'll be optimistic and say 10 pounds reduction in weight. Assuming you own the 2005 model, your dry weight according to Sport Rider (http://www.sportrider.com/bikes/2005/146_05_honda_cbr600rr_specs/) is 361 pounds. I'll also assume you weight 150lb, making it 511lbs total. So, to transform 511 to 501 what is the percentage we need to apply? Simple, 501/511 (rocket science!) = 0.9804 (98.04%). Now let's carry it over to our original Newtonian equation a=F/m. By applying this percentage, we get a=F/(.9804*m). Then by the power of multiplication, we transfer it over to the acceleration (hold on to your hats!) (1/.9804)*a=F/m ---> (1.01996)*a=F/m. Wow!!!! an increase of 1.996% (or 2%) in acceleration! worth every penny!!!!! Isn't science so cool!

Here is a picture of Newton, to which I pleasure myself every night.

Sexy man.

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lol freakin hilarious. NICE ONE!

Well let's transform that 5 or 10 pounds quoted earlier into a relative quantity called percentage (so fun!) Because the snow is melting here I'll be optimistic and say 10 pounds reduction in weight. Assuming you own the 2005 model, your dry weight according to Sport Rider (http://www.sportrider.com/bikes/2005/146_05_honda_cbr600rr_specs/) is 361 pounds. I'll also assume you weight 150lb, making it 511lbs total. So, to transform 511 to 501 what is the percentage we need to apply? Simple, 501/511 (rocket science!) = 0.9804 (98.04%). Now let's carry it over to our original Newtonian equation a=F/m. By applying this percentage, we get a=F/(.9804*m). Then by the power of multiplication, we transfer it over to the acceleration (hold on to your hats!) (1/.9804)*a=F/m ---> (1.01996)*a=F/m. Wow!!!! an increase of 1.996% (or 2%) in acceleration! worth every penny!!!!! Isn't science so cool!

Here is a picture of Newton, to which I pleasure myself every night.

Sexy man.

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But then it seems to reduce the acceleration. So theoretically, you are correct, but algabreically, I'm not seeing it.

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dude. you're kidding me.

But then it seems to reduce the acceleration. So theoretically, you are correct, but algabreically, I'm not seeing it.

IF A = B / C

THEN (1/D)*A = (1/D)*(B/C) = B/(C*D)

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